A man riding a bicycle form his house at 10km/h and reaches his office late by 6 min. He increases his speed by 2km/h and reaches 6 min before. How far is the office form his house?
Correct Answer: 12 km
Explanation:
Here, a = 10 km/h
b = ( 10 + 2 ) = 12 km/h,
t1 = 6 min = 1/10 h
and t2= 1/10 h.
∴ Required distance = ab( t1 + t2 )/(b - a)
= 10 x 12 x ( 1/10 + 1/10 ) /(12 - 10) = (10 x 12 x 1)/(5 x 2) = 12km
