A man travels the first part of his journey at 20 km/h and the next at 70 km/h, covering the entire journey at an average speed of 50 km/h. What is the ratio of the distance that he covered at 20 km/h to that he covered at 70 km/h?

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Accepted Answer

x/20 + y/70 = (x + y)/50 ⇒ (70x + 20y)/1400 = (x + y)/50 ⇒ 42x = 8y ⇒ x/y = 4/21

A man travels the first part of his journey at 20 km/h and the next at 70 km/h, covering the entire journey at an average speed of 50 km/h. What is the ratio of the distance that he covered at 20 km/h to that he covered at 70 km/h?

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