Two cars, a Maruthi and a Toyato, start at the same time in opposite directions from two distinct points A and B. Starting from A, the Maruthi reaches B in 6 hrs 20 minutes and the Toyato starting from B, reaches A in 4 hrs 45 minutes. What is the speed of the Toyato, if the speed of the Maruthi is 60 Km/h?

Let the distance between A and B = D

Given the speed of maruthi = 60 kmph

Maruthi reaches from A to B in 6 hrs 20 min = 6 + 20/60 = 6 1/3 hrs

Now, the distance between A & B = D = speed x time = 60 x 19/3 = 380 kms

As the distance is same for toyato also,

given time for toyato = 4 hrs 45 min = 4 + 45/60 = 4 3/4 = 19/4 hrs

speed of toyato = distance/time = 380/19/4 = 380 x 4/19 = 80 kmph.