10 men and 8 women together can complete a work in 5 days. Work done by one women in day is equal to half the work done by man in 1 day. How many days will it take for 4 men and 6 women to complete that work?

According to the question,
1 man = 2 women
∴ 10 men + 8 women = (20 + 8) women = 28 women
4 men + 6 women = (8 + 6) women = 14 women
Given, M₁ = 28, M₂ = 14, D₁ = 5, D₂ = ?
and W₁ = W₂ = 1
According to the formula, M₁D₁W₂= M₂D₂W₁
⇒ 28 x 5 x 1 = 14 x D₂ x 1
∴ D₂ = (28 x 5)/14 = 10 days