A and B can do a work in 4 hours and 12 hours respectively. A starts the work at 6 AM and they work alternately for one hour each. When will the work be completed?
Correct Answer: 6 days
Explanation:
Work donee by A and B in the first two hours, working alternatively = First hour A + Second hour B = (1/4) + (1/12) = 1/3.
Thus, the total time required to complete the work = 2 (3) = 6 days
