A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
Correct Answer: 60
Explanation:
(A + B)'s 20 day's work =
❨
1
x 20
❩
=
2
.
30
3
Remaining work =
❨
1 -
2
❩
=
1
.
3
3
Now,
1
work is done by A in 20 days.
3
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
