A and B together can do a piece of work in 12 days which B and C together can do in 16 days. After A has been working at it for 5 days and B for 7 days, C takes up and finishes it alone in 13 days. In how many days, C alone can do the work?

(A + B)'s one day work = 1/12
(B + C)'s one day work = 1/16
Now, from the question,
A's 5 days work + B's 7 days work + C's 13 days work = 1
⇒ A's 5 days work + B's 5 days work + B's 2 days work + C's 2 days work + C's 11 days work = 1
(A + B)'s 5 days work + (B + C)'s 2 days work + C's 11 days work = 1
⇒ 5/12 + 2/16 + C's 11 days work = 1
⇒ C's 11 days work = 1 - (5/12 + 2/16) = 11/24
⇒ C's 1 day work = (11/24) x 11 = 1/24
Hence, C can do this work in 24 days.