A can do a certain job in 10 days. B is 60% more efficient than A. The number of days, it takes B to do the same piece of work is?
Correct Answer: 62/3
Explanation:
1 day work of A = 1/10 = 0.1
1 day work of B = 1/10 + 60% of 1/10 = 0.1 + 0.06 = 0.16
So number of days taken by B to complete the work = 1/0.16
= 62/3
