A contractor undertook to do a certain piece of the work in 18 days. He employed certain number of men but 12 of them being absent from the very 1st day, the rest could finish the work in 30 days . Find the number of men originally employed.
Correct Answer: 30
Explanation:
Let the number of the men at the beginning = N
Given, M1 = N, M2 = N - 12, D1 = 18 and D2 = 30 According to the formula
M1D1 = M2D2
⇒ N x 18 = (N - 12) x 30
⇒ 3N = 5N - 60
⇒ 2N = 60
∴ N = 30
