The efficiency of Romil is twice that of Sanjay and he can finish a work in 4 h less than the time taken by Sanjay. If both of them work together they can finish the same work in?
Correct Answer: 8 / 3 h
Explanation:
As the efficience of Romil is twice that of Sanjay, Romil, will take x h for completeion of the work, when Sanjay is taking 2x h.
Given, 2x - x = 4
⇒ x = 4
Hence, they take = 1/(1/4 + 1/8) = 8/3 h
