Ten men and eight women together complete a work in 5 days. One woman’s 1-day work equals half of one man’s 1-day work. In how many days will four men and six women complete the same work?
Aptitude
Time and Work
Difficulty: Easy
Choose an option
Answer
Correct Answer: 10 days
Explanation
Introduction / Context:Use the given equivalence (1 woman = 1/2 man) to convert all workers to man-equivalents, then compute time for the smaller team.
Given Data / Assumptions:
- 10 men + 8 women → 5 days.
- 1 woman = 1/2 man.
Concept / Approach:Compute the total work in man-days, then divide by the rate of 4 men + 6 women in man-equivalents.
Step-by-Step Solution:
Equivalent men for (10, 8) = 10 + 8*(1/2) = 14Job size = 14 * 5 = 70 man-daysEquivalent men for (4, 6) = 4 + 6*(1/2) = 7Time = 70 / 7 = 10 daysVerification / Alternative check:Half-efficiency rule applied consistently across both teams yields an exact integer.
Why Other Options Are Wrong:They miscompute either the man-equivalent conversion or the final division.
Common Pitfalls:Using 2 women = 1 man inconsistently; ensure consistent conversion on both teams.
Final Answer:10 days