A supplies 20 men who work 8 hours per day for 6 days. B supplies 15 men working 9 hours per day for 7 days. C supplies 10 men working 6 hours per day for 8 days. If ₹ 636 is paid for all the labour, what is C's share?
Correct Answer: ₹ 128
Introduction / Context:When total payment is split among contributors, the share is proportional to the total man-hours supplied (assuming equal productivity). Compute each party’s man-hours, take the fraction for C, and multiply by the total payment.
Given Data / Assumptions:
- A: 20 men × 8 h/day × 6 days.
- B: 15 men × 9 h/day × 7 days.
- C: 10 men × 6 h/day × 8 days.
- Total payment = ₹ 636.
Concept / Approach:Share ∝ man-hours. Compute A, B, C man-hours; then C’s share = (C man-hours / total man-hours) * 636.
Step-by-Step Solution:
A man-hours = 20 * 8 * 6 = 960.B man-hours = 15 * 9 * 7 = 945.C man-hours = 10 * 6 * 8 = 480.Total man-hours = 960 + 945 + 480 = 2385.C’s fraction = 480 / 2385 = 32 / 159.C’s share = 636 * (32/159) = 128.Verification / Alternative check:Proportionality method is standard for wage division; arithmetic confirms exact ₹ 128.
Why Other Options Are Wrong:Other values do not match the man-hour proportion 32/159.
Common Pitfalls:Using men × days only and forgetting the hours factor; rounding mid-step.
Final Answer:₹ 128