A woman fills a bucket in 6 minutes. 1845 buckets have to be filled from 8 am. to 9:30 am. How many woman employees should be employed for this task?

We know that,  $\frac{M1 \times D1}{W1} = \frac{M2 \times D2}{W2}$

Here M1 = 1, D1 = 6 min, W1 = 1 and M2 = M, D2 = 90 min, W2 = 1845

$\frac{1 \times 6}{1} = \frac{M \times 90}{1845}$ 

=> M = 123