If each edge of a cube is increased by 50%, find the percentage increase in Its surface area

Let the edge = a cm   

So increase by 50 % = a + a/2 = 3a/2  

Total surface Area of original cube =  $6a2$  

TSA of new cube =  $6\frac{3a}{2}2$ = $6\frac{9a2}{4}$=   $13.5a2$   

Increase in area =  $13.5a2-6a2$ = $7.5a2$  

  $7.5a2$ Increase % = $\frac{7.5a2}{6a2}\times 100$ = 125%