If the side of a cube is increased by 12%, by how much per cent does its volume increase?

Here, k = 12%
According to the formula,
Percentage increase in volume = [(1 + k/100)³ - 1] x 100%
= [(1 + 12/100)³ - 1] x 100%
= [(1.12)³ - 1] x 100%
= 0.404928 x 100% = 40.4928%