Given that, the height and radius of a right circular ,etal cone (solid) are 8 cm and 2 cm, respectively.
i.e., h = 8 cm and r = 2 cm
Let the radius of the sphere is R
Then, by condition,
1/3 π r2 h = 4/3 π R3 h
⇒ 4 x 8 = 4 R3
⇒ R3 = (2)3 = ⇒ R = 2
∴ Radius odf the sphere = 2 cm