Three consecutive integers form the lengths of a right-angled triangle. How many sets of such three consecutive integers is/are possible?

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let n-1, n, n+1 be 3 consecutive integers So (n+1)^2= n^2+ (n-1)^2 (n+1)^2-(n-1)^2= n^2 4n = n^2 So n = 0 or n = 4 n can’t be 0 as n-1 will be negative then So 3,4 and 5…

Three consecutive integers form the lengths of a right-angled triangle. How many sets of such three consecutive integers is/are possible?

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