Binary-weighted-input DAC resistor selection In a binary-weighted-input digital-to-analog converter, the values of the input resistors are deliberately chosen to be proportional to the binary weights of the corresponding input bits.

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
Binary-weighted DACs implement digital-to-analog conversion by summing scaled contributions from each bit. The most significant bit contributes half of full-scale, the next contributes one-quarter, and so on, requiring precise weighting in the hardware network.



Given Data / Assumptions:

  • Each bit controls a switch that connects a resistor (or current source) weighted by 2^n.
  • Resistor values or current magnitudes follow binary ratios: 1, 1/2, 1/4, ... of full-scale.
  • Ideal operation assumes perfectly matched components and switches.


Concept / Approach:
For a resistor-summing implementation, smaller resistance corresponds to larger contribution (higher conductance). Thus, resistor values are selected so conductance is proportional to the bit weight. Alternatively, current-steering versions use binary-weighted current sources. The common theme is binary proportionality to implement the sum.



Step-by-Step Solution:

Assign each bit a weight of 2^n relative to LSB.Choose resistor values so that conductance scales with 2^n (or equivalently resistance scales with 1/2^n).Sum node produces an analog voltage proportional to the digital code.Calibrate or trim if necessary to correct mismatch-induced errors.


Verification / Alternative check:
Simulate a ramp across all codes; verify monotonic steps and correct full-scale output based on resistor ratios.



Why Other Options Are Wrong:
“Incorrect” contradicts the fundamental structure of binary-weighted DACs. “Only true for R-2R” is wrong—the R-2R ladder is a different approach that avoids wide resistor spreads. “Valid only with current sources” ignores resistor-summing implementations.



Common Pitfalls:
Large resistor ratio spreads limit resolution; switch on-resistance and parasitics disturb exact weights; temperature coefficients degrade linearity.



Final Answer:
Correct

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