Choosing one question from each of three exercises: A test picks one question each from Exercise 7 (12 questions), Exercise 8 (18 questions), and Exercise 9 (9 questions). In how many ways can the three-question paper be formed?
Aptitude
Permutation and Combination
Difficulty: Easy
Choose an option
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A1944
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B2094
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C1894
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D2194
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ENone of these
Answer
Correct Answer: 1944
Explanation
Introduction / Context:Selecting one item from each of several independent pools uses the multiplication principle. Here we choose one question from each of three exercises with given counts.
Given Data / Assumptions:
- Exercise 7 has 12 questions.
- Exercise 8 has 18 questions.
- Exercise 9 has 9 questions.
- Choices are independent.
Concept / Approach:
- Total papers = 12 * 18 * 9.
Step-by-Step Solution:
12 * 18 = 216216 * 9 = 1944Verification / Alternative check:No overlaps or constraints exist, so simple multiplication applies directly.
Why Other Options Are Wrong:
- 2094, 1894, 2194 are arithmetic distractors, not equal to 12*18*9.
Common Pitfalls:
- Adding the counts instead of multiplying across independent choices.
Final Answer:1944