Let x be the greater real root of x^2 − 16 = 0 and y be the greater real root of y^2 − 9y + 20 = 0. Compare x and y.

Aptitude Quadratic Equation Difficulty: Easy
Choose an option
  • A
    if x > y
  • B
    if x ≥ y
  • C
    if x < y
  • D
    if x ≤ y
  • E
    if x = y

Answer

Correct Answer: if x < y

Explanation

Introduction / Context: Two quadratics with easily factorable forms allow immediate determination of greater roots. We then compare those values directly.

Given Data / Assumptions:

  • x^2 − 16 = 0 ⇒ roots ±4, greater x = 4.
  • y^2 − 9y + 20 = 0 ⇒ (y − 4)(y − 5) = 0 ⇒ roots 4 and 5, greater y = 5.

Concept / Approach: Factorization and identification of the larger root for each equation.

Step-by-Step Solution:

x = 4 (greater root of first).y = 5 (greater root of second).Therefore x < y.

Verification / Alternative check: Numeric comparison is straightforward; no alternative method needed.

Why Other Options Are Wrong: They contradict the ordering 4 < 5.

Common Pitfalls: Accidentally picking the smaller root 4 for y instead of 5; the prompt specifies the greater root.

Final Answer: if x < y

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