Difficulty: Easy
Correct Answer: frequency
Explanation:
Introduction / Context:Inductors behave differently under DC and AC. At DC an ideal inductor looks like a short (after transients), but in AC it resists current changes. The measure of this opposition is called inductive reactance, a frequency-dependent quantity essential for filters, matching networks, and resonant circuits.
Given Data / Assumptions:
Concept / Approach:The inductor voltage-current relationship is v = L * di/dt. Under sinusoidal excitation, i and v are sinusoidal; in phasor form, Z_L = j * 2π * f * L. The magnitude of this impedance is X_L = 2π * f * L. Hence, X_L scales linearly with frequency f and also with inductance L. When f increases, X_L increases proportionally; when f decreases toward zero, X_L tends to zero.
Step-by-Step Solution:
Write Z_L = j * 2π * f * L.Take magnitude: X_L = |Z_L| = 2π * f * L.Observe proportionality: X_L ∝ f (and ∝ L).Conclude: the inductor’s opposition to AC is directly proportional to frequency.Verification / Alternative check:Measure current through a fixed inductor driven by a fixed-amplitude source at two frequencies, f1 < f2. Since I ≈ V / X_L, current at f2 is smaller by the ratio f2/f1, confirming linear dependence on frequency.
Why Other Options Are Wrong:
resistance: resistors yield frequency-independent opposition (for ideal parts).applied voltage amplitude: changing V alters current but does not define X_L.wire length only: geometry affects L, but X_L’s direct proportionality is to f (and to L, not merely length).capacitance: belongs to capacitive reactance (X_C = 1 / (2π f C)), not inductive behavior.Common Pitfalls:Confusing X_L (reactance magnitude) with the complex j operator; forgetting that at very high frequency, parasitics can shift behavior from ideal.
Final Answer:frequency
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