Nozzle exit velocity formula (steam): select the correct relation Let K be the nozzle efficiency (or nozzle coefficient) and h d be the enthalpy (heat) drop during expansion per kilogram. Choose the correct expression for the theoretical…

Concept/Approach From steady adiabatic nozzle energy balance: V ≈ √(2 × K × Δh) with Δh in J/kg. With Δh (kJ/kg), conversion gives V (m/s) = 44.72 × √(K × hd) (since √(2 × 1000) ≈ 44.72). Final Answer V = 44.72 × √(K × hd)

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Nozzle exit velocity formula (steam): select the correct relation Let K be the nozzle efficiency (or nozzle coefficient) and h<sub>d</sub> be the enthalpy (heat) drop during expansion per kilogram. Choose the correct expression for the theoretical exit velocity V (m/s).

Difficulty: Easy

V = 44.72 × √(K × h_d)
V = 44.72 × (K × h_d)
V = 44.72 × √(h_d/K)
V = 44.72 × (h_d/K)

Correct Answer: V = 44.72 × √(K × h_d)

Explanation:

Concept/Approach

From steady adiabatic nozzle energy balance: V ≈ √(2 × K × Δh) with Δh in J/kg.
With Δh (kJ/kg), conversion gives V (m/s) = 44.72 × √(K × h_d) (since √(2 × 1000) ≈ 44.72).

Final Answer
V = 44.72 × √(K × h_d)

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