Difficulty: Easy
Correct Answer: False — shaft 'A' must have the greater diameter
Explanation:
Given data
Equal power P is transmitted by shafts 'A' and 'B'.Speeds: NA = 250 rpm, NB = 300 rpm.Same material and allowable shear stress (design criterion).
Concept/Approach
Power P = T·ω, so torque T = P/ω. Lower speed ⇒ lower ω ⇒ higher T for the same power.For a solid circular shaft at allowable shear stress τ: T = (π/16)·τ·D³ ⇒ D ∝ T1/3.
Step-by-step
ω ∝ N, thus TA/TB = ωB/ωA = NB/NA = 300/250 = 1.2.Therefore DA/DB = (TA/TB)1/3 ≈ (1.2)1/3 > 1.Hence shaft 'A' (slower) needs the larger diameter.
Common pitfall
Confusing high speed with larger diameter; actually, for equal power, lower speed requires higher torque and thus a larger diameter.
Final Answer
False — shaft 'A' must have the greater diameter.
Discussion & Comments