Difficulty: Easy
Correct Answer: 78%
Explanation:
Introduction / Context:This problem blends ratios with basic percentage calculations. We are given the gender composition of a college and the fraction of adult students within each gender, and we must find the overall percentage of students who are not adults. This is typical of demographic or survey-style aptitude questions where careful aggregation is key.
Given Data / Assumptions:
Concept / Approach:Use a ratio base to avoid cumbersome algebra. With 3 parts boys and 2 parts girls, compute adult counts in each group using the given percentages. Sum adult counts to get total adults. Then convert to a percentage of the whole. The non-adult percentage is 100% minus the adult percentage.
Step-by-Step Solution:
Let total students = 5k (boys = 3k, girls = 2k) Adult boys = 20% of 3k = 0.6k Adult girls = 25% of 2k = 0.5k Total adults = 0.6k + 0.5k = 1.1k Adult % = (1.1k / 5k) * 100 = 22% Non-adult % = 100% − 22% = 78%Verification / Alternative check:Pick actual numbers: if total is 500, boys = 300, girls = 200. Adults = 20% of 300 (60) + 25% of 200 (50) = 110 adults. Adult % = 110/500 = 22%; non-adults = 78%.
Why Other Options Are Wrong:58%, 67.5%, and 82.5% arise from mixing or averaging percentages incorrectly. 72% is an arbitrary nearby value but does not match the computed adult complement of 22%.
Common Pitfalls:Directly averaging 20% and 25% without weighting by the 3 : 2 ratio, or subtracting the wrong quantity from 100%. Weighted aggregation is essential.
Final Answer:78%
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