A train travels 50% faster than a car. Both start from A and reach B (75 km) at the same time, but the train loses 12.5 minutes at stations. What is the car's speed (km/h)?

The train is 50% faster than the car, but it has stoppage time. Equal arrival times imply the car’s running time equals the train’s running time plus stoppage.

Given data

• Distance AB = 75 km
• Train speed = 1.5 × car speed = 1.5c
• Stoppage time (train) = 12.5 min = 25/120 h
• Arrival times equal

Step-by-step calculationCar time = 75 / cTrain running time = 75 / (1.5c)Car time = Train running time + stoppage75 / c = 75 / (1.5c) + 25/12075 / c − 50 / c = 25/12025 / c = 25/120c = 120 km/h

VerificationCar time = 75 / 120 = 0.625 hTrain run time = 75 / 180 = 0.4167 h; add 0.2083 h stoppage = 0.625 h (matches)

Common pitfallsDon’t forget to convert 12.5 minutes to hours, and don’t set distances unequal—the distance is the same for both.

Final Answer120 km/h