Find out how many times 2, 3 and 7 have present together, and always 3 in middle and 2 and 7 places either side of 3? 1 1 1 1 3 3 2 2 2 3 7 7 3 3 3 6 6 4 7 3 2 4 9 8 7 7 3 2 3 3 3 4 4 2 3 7

Correct Answer: 4

Explanation:

Four times 3 present together with 2 and 7, where 2 and 7 present either side of 3.
1 1 1 1 3 3 2 2 [2 3 7] 7 3 3 3 6 6 4 [7 3 2] 4 9 8 7 [7 3 2] 3 3 3 4 4 [2 3 7]