C++ inheritance lookup: when a child (derived) class function is called on an object, where does the compiler look first for a matching function signature/name?

Introduction / Context:Name lookup and overload resolution in C++ proceed from the most specific scope outward. When invoking a member function on an object, the compiler tries to bind the call by first considering members of the object’s own (most-derived) class, then searching base classes as needed. This ordering affects which overload is chosen or whether a base member is hidden.

Given Data / Assumptions:

• Single or multiple inheritance may be present.
• Virtual dispatch is a runtime concept; name lookup and overload resolution occur at compile time.
• The question asks about the starting point of lookup, not virtual override binding.

Concept / Approach:

• Unqualified member lookup begins in the class of the object expression.
• If not found, lookup proceeds to immediate base classes, then further bases.
• Derived-class declarations can hide base-class members of the same name.

Step-by-Step Solution:

Verification / Alternative check:

Why Other Options Are Wrong:

• Immediate ancestor/base class: Searched only if not found in the object’s class.
• Descendant class: More derived than the current type does not exist for that object.
• None of the above: Incorrect because option A is precise.

Common Pitfalls:

• Confusing compile-time lookup with runtime virtual dispatch (which chooses the most-derived override at runtime).
• Forgetting that derived declarations can hide base overloads unless using-declarations are introduced.

Final Answer: