Difficulty: Easy
Correct Answer: A capacitance in parallel with the series combination of a resistance and an inductance
Explanation:
Introduction / Context:No physical inductor is ideal. Winding resistance and interwinding capacitance alter behavior at both low and high frequencies. A suitable equivalent circuit helps predict resonances, Q factor, and losses—critical in filters, RF chokes, and switch-mode power supplies.
Given Data / Assumptions:
Concept / Approach:A common small-signal model is L in series with R_s, representing copper loss, with a shunt (parallel) capacitance C_p modeling self-capacitance between turns or layers. This topology exhibits a self-resonant frequency where the inductive reactance and capacitive reactance cancel, beyond which the inductor can appear capacitive. Such a model matches measured impedance-versus-frequency curves for practical components.
Step-by-Step Solution:
Identify series elements: L + R_s capture inductance and DC resistance.Add parallel C_p to represent turn-to-turn capacitance.Compare with options and select the one describing C in parallel with (R + L in series).Verification / Alternative check:Impedance analyzers reveal a peak and phase crossover at the self-resonant frequency, predicted by the R_s–L series branch shunted by C_p.
Why Other Options Are Wrong:
Common Pitfalls:Neglecting C_p at high frequency, leading to incorrect assumptions that inductors stay inductive across all frequencies.
Final Answer:A capacitance in parallel with the series combination of a resistance and an inductance
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