Equality vs. repetition — identify which pair is not equal: Which pairs of sets below are not equal? (Remember duplicates do not change a set.)
-
A(a) A = {1, 3, 3, 1}, B = {1, 4}
-
B(b) A = {x: x + 2 = 2}, B = {0}
-
C(c) A = {1, 3, 4, 4}, B = {3, 1, 4}
-
D(d) A = {1,1/2,1/3,... }, B = {1/n : n ∈ N }
-
EAll are equal
Answer
Correct Answer: (a) A = {1, 3, 3, 1}, B = {1, 4}
Explanation
Introduction / Context:Two sets are equal if they have exactly the same elements, ignoring order and repetitions. We test each pair accordingly.
Given Data / Assumptions:
- (a) A = {1,3}, B = {1,4}
- (b) A = {x : x + 2 = 2} → {0}; B = {0}
- (c) A = {1,3,4}; B = {3,1,4}
- (d) A = {1, 1/2, 1/3, ...}; B = {1/n : n ∈ N}
Concept / Approach:Reduce duplicates, then compare elements one-to-one. For (d), both describe the same infinite set.
Step-by-Step Solution:(a) {1,3} ≠ {1,4} → not equal(b) {0} = {0} → equal(c) {1,3,4} = {1,3,4} → equal(d) identical descriptions → equal
Verification / Alternative check:For (b) solve x + 2 = 2 → x = 0 confirming equality.
Why Other Options Are Wrong:They assert non-inequality when pairs are equal; only pair (a) differs.
Common Pitfalls:Letting repetition or order mislead; sets ignore both.
Final Answer:(a) A = {1, 3, 3, 1}, B = {1, 4}