Question 1

The average of runs of a cricket player of 10 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4 ?

Accepted Answer

Average = total runs / no.of innings = 32 So, total = Average x no.of innings = 32 x 10 = 320. Now increase in avg = 4runs. So, new avg = 32+4 = 36runs Total runs = new avg x new no. of innings = 36 x 11 = 396 Runs made in the 11th inning = 396 - 320 = 76

Question 2

The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero ?

Accepted Answer

Average of 20 numbers = 0. Sum of 20 numbers = (0 * 20) = 0. It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (- a).

Question 3

A grocer has a sale of Rs 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6500 ?

Accepted Answer

Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009. Required sale = Rs.[(6500 x 6) - 34009] = Rs. (39000 - 34009) = Rs. 4991.

Question 4

The average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ?

Accepted Answer

Total weight increased = (8 x 2.5) kg = 20 kg. Weight of new person = (65 + 20) kg = 85 kg.

Question 5

The average weight of a class of 24 students is 35 kg. If the weight of the teacher be included, the average rises by 400 g. The weight of the teacher is :

Accepted Answer

Weight of the teacher = (35.4 x 25 - 35 x 24) kg = 45 kg.

Question 6

The mean temperature of Monday to Wednesday was 37 degree celsius and of Tuesday to Thursday was 34 degree celsius . If the temperature on Thursday was (4/5) th that of Monday, the temperature on Thursday was?

Accepted Answer

Let, temperature of Monday = a Temperature of Tuesday = b Temperature of Wednesday = c Temperature of Thursday = 4a/5 Sum of temperatures of Monday to Wednesday = 3×37 = 111 => a+b+c=111------(1) Sum of temperatures of Tuesday to Thursday = 3×34 = 102 b+c+(4a/5) = 102 ------(2) (1)-(2)=> a−(4a/5)=111−102 a/5=9 a=45 Temperature on Thursday = 4a/5 =4×45/5 =36

Question 7

A pupil's marks were wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by half. The number of pupils in the class is :

Accepted Answer

Let there be x pupils in the class. Total increase in marks = (x * 1/2) = x/2. x/2 = (83 - 63) => x/2 = 20 => x = 40.

Question 8

The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is :

Accepted Answer

Correct Sum = (36 * 50 + 48 - 23) = 1825. Correct mean = = 1825/50 = 36.5

Question 9

Of the four numbers, whose average is 60, the first is one-fourth of the sum of the last three. The first number is :

Accepted Answer

Let the first number be x, Then, sum of the four numbers = x + 4x = 5x. so, 5x/4 = 60 or x = (60 * 4) / 5 = 48.

Question 10

Out of 9 persons, 8 persons spent Rs. 30 each for their meals. The ninth one spent Rs. 20 more than the average expenditure of all the nine. The total money spent by all of them was :

Accepted Answer

Let the average expenditure be Rs. x Then, 9x=[(8*30)+(x+20)]<=>9x =x+260 <=> x =32.50 Total money spent = 9x = Rs. (9 x 32.5O) = Rs 292. 50

Question 11

The average of 11 numbers is 10.9. If the average of the first six numbers is 10.5 and that of the last six numbers is 11.4, then the middle number is :

Accepted Answer

Middle numbers = [(10.5 x 6 + 11.4 x 6) - 10.9 x 11] = (131.4 - 119-9) = 11.5.

Question 12

The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the …

Accepted Answer

Let the average age of the whole team be x years. 11x - (26 + 29) = 9 (x - 1) => 11x - 9x = 46 => 2x = 46 => x = 23. So, average age of the team is 23 years.

Question 13

The average temperature of the town in the first four days of a month was 58 degrees. The average for the second, third, fourth and fifth days was 60 degrees. If the temperatures of the first and fifth days were in the ratio 7 : 8, then what is the …

Accepted Answer

Sum of temperatures on 1st, 2nd, 3rd and 4th days = (58 * 4) = 232 degrees ... (1) Sum of temperatures on 2nd, 3rd, 4th and 5th days - (60 * 4) = 240 degrees ....(2) Subtracting (1) From (2), we get : Temp, on 5th day - Temp on 1st day = 8 degrees. Let the temperatures on 1st and 5th days be 7x and 8x degrees respectively. Then, 8x - 7x = 8 or x = 8. Temperature on the 5th day = 8x = 64 degrees.

Question 14

The average monthly salary of the employees of a firm is Rs.60 out of the employees 12 officers get an average of Rs.400 per month and the rest an average of Rs. 56 per month , Find the number of emp

Accepted Answer

The actual average salary of 12 officers = 400 therefore Total salary of 12 officers = 400 x 12 = 4800 Average of these 12 officers as a whole =60 Total salary of 12 officers as a whole = 60 x 12 = 720 The total salary of rest = 4800 - 720 = 4080 The difference in average of the rest of officers = 60 - 56 = 4 Rest of the officers = 4080/4=1020 Total number of employees = 1020 + 12 = 1032

Question 15

The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is :

Accepted Answer

Lot the total number of workers be v Then, 8OOOv = (12000 * 7) + 6000 (v - 7) <=> 2000v = 42000 <=> v = 21.

Question 16

A team of 8 persons joins in a shooting competition. The best marksman scored 85 points. If he had scored 92 points, the average score for the team would have been 84. The number of points, the team scored was :

Accepted Answer

Let the total score be x. (x + 92 - 85) / 8 = 84. So, x + 7 = 672 => x = 665.

Question 17

A certain factory employed 600 men and 400 women and the average wager was Rs. 25.50 per day, If a woman got Rs. 5 less than a man, then what are their daily wages ?

Accepted Answer

Let the daily wage of a man be Rs. x. Then, daily wage of a woman = Rs. (x - 5). Now, 600x + 400 (x - 5) = 25.50 * (600 + 400) <=> 1000x = 27500 <=> x = 27.50. Man's daily wages = Rs. 27.50; Woman's daily wages = (x - 5) = Rs. 22.50.

Question 18

A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is :

Accepted Answer

Since the month begins with a Sunday, so there will be five Sundays in the month, Required average = (510 * 5 + 240 * 25) / 30 = 8550/30 = 285.

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