Given equation are 6x + 3y = 7xy
⇒ (6/y) + (3/x) = 7 .....(i)
And 3x + 9y = 11xy
⇒ (3/y) + (9/x) = 11 .....(ii)
On multiplying Eq. (ii) by 2 and subtracting from Eq. (i), we get
(6/y) + (3/x) = 7
(6/y) + (18/x) = 22
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- 15/x = - 15
∴ x = 1
On putting this value in Eq. (i), we get
(6/y) + 3 = 7
∴ 6/y = 4
∴ y = 6/4 = 3/2
