Let the cost of one chair be ₹ x
and cost of one table be ₹ y.
By given condition,
10x + 6y = 6200 ..(i)
and 3x + 2y = 1900
⇒ 9x + 6y = 5700 ...(ii)
On subtracting Eq. (ii), we get
x = ₹ 500
From Eq (i),
5000 + 6y = 6200
⇒ 6y = 1200
∴ y = ₹ 200
The cost of 4 chair and 5 tables
= 4x + 5y
= 2000 + 1000
= ₹ 3000