If 10 0.3010 = 2, then find the value of log 0.125 125.?

Exp. = log_0.125125 = log₂^-3 5³ = - 3/3log₂5 = -log₂5
∵ 10^0.3010 = 2
⇒ log₁₀2 = 0.3010
∵ log₁₀5 = log₁₀10/2 = log₁₀10-log₁₀2
= 1-0.3010 = 0.6990
∴ -log₂5 = - log₁₀⁵ / log₁₀²
= - 0.6990 / 0.3010 = - 699/301