If log 8 x + log 4 x + log 2x =11, then the value of x is?

∵ log₂³ x¹ +log₂² x¹ + log₂x = 11
⇒ 1/3log₂x + 1/2log₂x + log₂x = 11
⇒ (1/3 + 1/2 +1)log₂x = 11
⇒ 11/6log₂x = 11
⇒ log₂x = 11 x 6 / 11 =6
∴ x = 2⁶ = 64