Question 1

A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and 24% of 50 p coins are removed, the percentage of money removed from the bag is nearly :

Accepted Answer

Total money = Rs.[600*(25/100)+1200*(50/100)]= Rs. 750. 25 paise coins removed = Rs. (600*12/100) = 72. 50 paise coins removed = Rs. (1200*24/100)= 288. Money removed =Rs.(72*25/100+288*50/100) = Rs.162. Required percentage = (162/750*100)% = 21.6 %.

Question 2

If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ?

Accepted Answer

The original fraction is 25 51 × 350 + 100 150 + 100 = 15/17.

Question 3

The sum of the number of boys and girls in a school is 150. if the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is :

Accepted Answer

We have : x + (x% of 150 )= 150 => x+(x/100)*150] = 150 => 5 2 x = 150 => x = (150*2)/5 = 60

Question 4

In a class of 80 students and 5 teachers, each student got sweets that are 15% of the total number of students and each teacher got sweets that are 25% of the total number of students. How many sweets were there?

Accepted Answer

Total number of sweets = 80 x 15 x 80/100 + 5 x 80 x 25/100 = 960 + 100 = 1060

Question 5

One hour is what percent of a day?

Accepted Answer

A day has 24 hrs => If 24 hrs - 100 Then 1 hr = ? 100/24 = 4.16%

Question 6

The difference between a number and its two-fifth is 510. What is 10% of that number ?

Accepted Answer

Let the number be x. Then, x-(2/5)x = 510 => 3x/5 =510 =>x =[510 * ( 5/3)] =850 10 % 0f 850 = 85.

Question 7

A number is increased by 20% and then decreased by 20%, the final value of the number is ?

Accepted Answer

Here, x = 20 and y = - 20 Therefore, the net % change in value = x + y + x y 100 % = 20 + - 20 + 20 × - 20 100 % or - 4% Since the sign is negative, there is a decrease in value by 4%.

Question 8

A shopkeeper’s earning increases by 25% in first year but decreases by 4% in the next and so on. After 5 years his total earnings would be Rs. 72,000. What is his present earning?

Accepted Answer

Let his present earnings be Rs. p ATQ, (125/100) x (96/100) x (125/100) x (96/100) x (125/100) x p = 72000 p = Rs. 40,000.

Question 9

When the price of rice decrease by 10%, a girl could buy 1 kg more for Rs. 270. Then, the original price of the rice per kg is

Accepted Answer

From the given data, When the price of rice is decreased by 10%, the value of Rs. 270 would become 270 x 100/90 = 300 Now, the value 270 becomes 300 And given, the girl could buy 1 kg extra for that value Change in value = 300 - 270 = Rs. 30 Therefore, 1 kg extra rice she can get for Rs. 30 => The original price of rice = Rs. 30/kg. As she gets only 9 kgs for Rs. 270 before 10% discount, now after discount she gets 10 kgs instead of 9 kgs for Rs. 270.

Question 10

An agent, gets a commission of 2.5% on the sales of cloth. If on a certain day, he gets Rs. 12.50 as commission, the cloth sold through him on that day is worth

Accepted Answer

Let the total sale be Rs. x. Then, 2.5%. of x = 12.50 => (25/100 * 1/100 * x) = 125/10 => x = 500.

Question 11

45% of 750 - 25% of 480 = ?

Accepted Answer

Given expression = (45 x 750/100) - (25 x 480/100) = (337.50 - 120) = 217.50

Question 12

How many litres of pure acid are there in 8 litres of a 20% solution ?

Accepted Answer

Quantity of pure acid = 20% of 8 litres = ((20/100)*8) litres = 1.6 litres.

Question 13

56% of 225 + 20% of 150 = ? - 109 Find the value of '?' in the above equation

Accepted Answer

Given 56% of 225 + 20% of 150 = ? - 109 we know that a% of b = b% of a Now, 225% of 56 + 20% of 150 = ? - 109 200% of 56 + 25% of 56 + 20% of 150 = ? - 109 112 + 14 + 30 = ? - 109 ? = 112 + 14 + 30 + 109 ? = 264

Question 14

If P is 140, which is 40% more than Q, then 3/25 of Q is

Accepted Answer

From the given data, P = 140 But it is given that, 40% of Q + Q = 140 = P => Q + [40Q/100] = 140 => [100Q + 40Q]/100 = 140 => 140Q = 140 x 100 => Q = 100 Now, 3/25 of Q = (3/25) x 100 = 3 x 4 = 12 Required 3/25 of Q = 12.

Question 15

A batsman scored 120 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets ?

Accepted Answer

Number of runs made by running = 120 - (3 x 4 + 8 x 6) = 120 - (60) = 60 Required percentage = [(60/120)*100] % = 50%

Question 16

In an examination, 34% of the students failed in Mathematics and 42% faiied in English. If 20% of the students failed in both the subjects, then the percentage of students who passed in both the subjects was :

Accepted Answer

n (A) = 34, n (B) = 42, n (A ∩ B) = 20. So, n (A U B) = n (A) + n(B) - n(A ∩B) = 34 + 42 - 20 = 56. Percentage failed in either or both the subjects = 56. Hence, percentage passed = (100 - 66)% = 44%.

Question 17

While purchasing one item costing Rs. 400, I had to pay the sales tax at 7% and on another costing Rs. 6400, the sales tax was 9%. What percent of the sales tax I had to pay, taking the two items together on an average ?

Accepted Answer

Total sales tax paid = 7% of Rs, 400 + 9% of Rs. 6400 =Rs. (7/100)*400 + (9/100)*6400 = Rs. (28 + 576) = Rs. 604. Total cost of the items = Rs. (400 + 6400) = Rs. 6800. Required percentage =(604/6800*100) % = 8 15 17 %.

Question 18

Abhinav scores 80% in physics and 66% in chemistry and the maximum marks of both the papers are 100. what percent does he score in maths which is of 200 marks, if he scores 80% marks in all the three subjects:

Accepted Answer

80 100 + 66 100 + x 200 = 320 400 =>x = 174 => 87%

Question 19

If price of rice increased by 25%, so that a man is can able to purchase 5 kg less rice in Rs. 500. Find the original price of rice per kg ?

Accepted Answer

Let the original price of rice be Rs. x Let rice a man can buy for Rs. 500 at rs. x/kg be = R kgs From given data, for Rs. 500 x ---- R kgs (x + 25x/100) ---- (R - 5) kgs => Rx = (R - 5)(x + 25x/100) => Rx = (R - 5)(125x/100) => 100Rx = 125Rx - 625x => R = 25 So at rate of Rs. x/kg, man get 25 kgs for Rs. 500 => x = 500/25 = Rs. 20

Percentage Questions