Question 1

A woman suffered 20% loss on first investment and made 10% profit at second investment and 12 ½% profit on the third investment. If the invested amount be in the ratio of 4 : 5 : 3, find her profit percentage?

Accepted Answer

From the given data, let the amounts invested be 4p, 5p and 3p Net profit = Total profit - Total loss = 10x5p/100 + 25x3p/200 - 20x4p/100 = 0.875p - 0.8p = 0.075p Therefore, profit% = (Net profit/Total investment) x 100 = 0.075 x 100/12 = 0.0625%

Question 2

Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the am…

Accepted Answer

Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then, As we know: Simple interest (S.I.) = PTR/100 (a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200 = 10a + 12b + 15c = 320000 .........(1) Now, c = 240% of b = 12b/5 .........(2) And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3) From (1), (2) and (3), we have 16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000 ∴ Sum invested in Scheme Y = Rs.5000.

Question 3

In order to maximize his gain, a shopping mall owner decides to reduce the price of electronics goods by 20% and as a result of this, the sales of electronics increase by 40%. If, as a result of these changes, he is able to increase his weekly colle…

Accepted Answer

It won't requires that much solving. Here given the increase in weekly collection by Rs. 1,05,000 That is this increase denotes for all 7 days. => Gross Collection increase per day = Rs . 1 , 05 , 000 7 = Rs . 15 , 000 Hence, the gross collection increase per day = Rs. 15,000.

Question 4

74.99% of 1299 + 8.98% of 1899 = ?

Accepted Answer

74.99% of 1299 + 8.98% of 1899 = ? ? = 75 x 1400 100 + 9 x 1800 100 ? = 1050 + 162 ? = 1212 .

Question 5

Arun’s weight is 140% of Akhil’s weight. Nani’s weight is 90% of Shreyon’s weight. Shreyon’s weight is twice as much as Akhil’s. What percentage of Arun’s weight is Nani’s weight?

Accepted Answer

Let Akhil's weight = p kg => Shreyon's weight = 2p kg Nani's weight = 0.9 x 2p = 1.8p kg => Arun's weight = 1.4p kg Required percentage = 1 . 4 p 1 . 8 p x 100 = 77.8% ~= 78%

Question 6

What will come in place of the question mark (?) in the following question ? 52.5% of 800 + 30.5% of 2800 = ? + 87.30

Accepted Answer

52.5% of 800 + 30.5% of 2800 = ? + 87.30 420 + 854 - 87.30 = ? 1274 - 87.30 = ? ? = 1186.70

Question 7

A sales boy is allowed 412 % discount on the total sales made by him plus a bonus of 14 % on the sales over Rs.12,000.If his total earnings were Rs.2400, then his total sales(in Rs.) are ?

Accepted Answer

Let the total earnings be Rs.x Then 4 1 2 % of x + 1 4 % of (x-12000) =2400 ⇒ 9 2 × x 100 + 1 4 × x - 12000 100 = 2400 => x=50,589.47

Question 8

In a competitive examination, the average marks for the entire examination was 60 marks. If 20% of the applicants scored 85 marks and 25% scored 95 marks. What was the average marks of the remaining applicants in the examination ?

Accepted Answer

Let the total applicants be 100 Then, 20% got 85 marks i.e 20 x 85 = 1700 and 25% got 95 marks i.e 25 x 95 = 2375 Now, the remaining applicants are 55 and let the average marks scored by them be x. Therefore, 2375 + 1700 + 55x = 60 × 100 6000 - 4075 = 55x 55x=1925 x=35.

Question 9

If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ?

Accepted Answer

Let X = Time taken for each of Type B Problems(100 Problems) And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180 100X + 100X = 180 200X = 180 min X = 180/200 X = 0.90 min By convertiing into seconds, X = 0.90 x 60 seconds X = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds = 5400/60sec = 90 minutes.

Question 10

Two numbers are 35% and 42% are less than a third number .How much percent is the second number less than the first ?

Accepted Answer

I II III 65 58 100 65 -------- 7 100 ------ ? => 10.769%

Question 11

Express 6.72 % in ratio ?

Accepted Answer

6.72/100 = 672/10000 = 42/625

Question 12

1/2 as a percentage?

Accepted Answer

1/2 as a percentage means 1/2 = 0.5 in decimal Now, in percentage means 0.5 x 100% = 50%.

Question 13

Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each gentleman received twice the paise as each lady received. Find the number of gentlemen in the family?

Accepted Answer

Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115 ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23 Hence, required number of gentlemen in the family = x = 23.

Question 14

3 is what percent of 5?

Accepted Answer

Here it is asked that 3 is what percent of 5 Let 3 is K percent of 5. => K x 5/100 = 3 => K = 300/5 = 60 Hence, 3 is 60% of 5.

Question 15

In a class of 80 students and 5 teachers, each student got sweets that are 15% of the total number of students and each teacher got sweets that are 25% of the total number of students. How many sweets were there?

Accepted Answer

From the given data, 80 x 15/100 of 80 + 5 x 80 x 25/100 = 960 + 100 = 1060.

Question 16

If 1/8 of a pencil is black, 1/2 of the remaining is white and the remaining, 3/2cm is blue. Find the total length of the pencil?

Accepted Answer

Let the total length of the pencil = x cms From the given data, 'x/8' is black Remaining part = x - x/8 = 7x/8 1/2 of 7x/8 is white => 7x/16 is white (Remaining part is 7x/16) And given that the remaining part is blue and is 3 1/2 cm = 7/2 = 3.5 cm That remaining part = 7x/16 Therefore, 7x/16 = 7/2 x = 16/2 = 8 Hence, the total length of the pencil = x = 8 cm.

Question 17

The price of a car is increased by 25%, by how much percent, must the new price of this car be decreased to restore its original price ?

Accepted Answer

Suppose that the original price of the car = Rs. x Then new price of the car => (x) + (x ×25/100) = Rs. 5x/4 To restore the original price, the new price must be decreased by 5x/4 − x = x/4 So required percentage =(x/4)/(5x/4) × 100% = 20%

Question 18

40% of 80?

Accepted Answer

Here 40% of 80 is given as 40 100 x 80 = 8 x 4 = 32

Question 19

5% of 40,000 is

Accepted Answer

5% of 40,000 = 5 100 × 40 , 000 = 5 × 400 = 2 , 000 Hence, 5% of 40,000 = 2,000.

Percentage Questions