Question 1

In a hoel, 60% had vegetarian lunch while 30% had non-vegetaian lunch and 15% had both types of lunch. If 96 people were present, how many did not eat either type of lunch ?

Accepted Answer

n (A) = (60/100 * 96) = 288/5, n (B) = (30/100 * 96) = 144/5, n (A ∩ B) = (15/100 * 96) = 72/5. n(A ∪ B) = n (A) + n (B) - n (A ∩ B) = 72. So, people who had either or both types of lunch = 72. Hence, people who had neither type of lunch = (96 - 72)= 24.

Question 2

2 is what percent of 50?

Accepted Answer

Let p% of 50 is 2 => p x 50/100 = 2 => p = 4% Hence, 2 is 4 percent of 50.

Question 3

1/4 of 12?

Accepted Answer

1/4 of 12 = 1/4 x 12 = 3 Hence, 1/4 of 12 = 3.

Question 4

A’s salary is 50% more than B’s. How much percent is B’s salary less than A’s?

Accepted Answer

Let the salary of B be 100 Salary of A = 150% B’s salary less than A = (150-100)/150 X 100 = 100/3 = 33.33%

Question 5

The price of an item is decreased by 25%. What percent increase must be done in new price to get the original price?

Accepted Answer

Let the price of an item be 100After 25% decrease, price of item = 75Increase in price to get the original price = 100-75 = 25% increase to get the original price = 25/75 X 100 = 100/3 = 33.33%

Percentage Questions