The chance of throwing a total of 3 or 5 or 11 with two dics is?

∵ Probability for 3 = (1, 2), (2, 1) = 2/36
⇒ Probability for 5 = (1, 4), (2, 3), (3, 2), (4, 1)= 4/ 36
⇒ Probability for 11 (5, 6), (6, 5) = 2/36
∴ Reqd . Probability = 2/36 + 4/36 + 2/36 = 8/36 = 2/9