In a charity show tickets numbered consecutively from 101 through 350 are placed in a box. What is the probability that a ticket selected at random (blindly) will have a number with a hundredth digit of 2?

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Accepted Answer

250 numbers between 101 and 350 i.e. n(S)=250 n(E)=100th digits of 2 = 299−199 = 100 P(E)= n(E)/n(S) = 100/250 = 0.40

In a charity show tickets numbered consecutively from 101 through 350 are placed in a box. What is the probability that a ticket selected at random (blindly) will have a number with a hundredth digit of 2?

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