Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ?

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Accepted Answer

n(S) = 20 n(Even no) = 10 = n(E) n(Prime no) = 8 = n(P) P(E U P) = 10/20 + 8/20 - 1/20 = 17/20

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