Find the sum of three numbers which are prime to one another such that the product of the first two is 437 and that of the last two is 551?

From the question we see that the second number is a common factor of the two products and since the numbers are prime to one another. It is their . H. C. F . and is, therefore, 19.
∴ The first number = 437 / 19 = 23
and the third number = 551 / 19 = 29
Hence, the number are 23, 19 and 29
∴ Sum = 23 + 19 + 29
= 71.