What least number must be subtracted from 1936, so that the remainder when divided by 9, 10, 15 will leave in each case the same remainder 7?

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Accepted Answer

The L.C.M of 9, 10, 15 = 90 On dividing 1936 by 90, the remainder = 46 But a part of this remainder = 7 Hence, the two numbers = 46 - 7 = 39.

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