A man has four copper rods whose lengths are 52 m, 65 m, 78 m, 91 m, respectively. This man wants to cut pieces of same length from each of four rods. what is the least number of total pieces if he is to cut without any wastage?

Question

Accepted Answer

The pieces cut from four rods is least, so length of the pieces is the HCF of 52, 65, 78 and 91 which is 13. ∴ Number of pieces cut =(52 + 65 + 78 + 91)/13 = 22

A man has four copper rods whose lengths are 52 m, 65 m, 78 m, 91 m, respectively. This man wants to cut pieces of same length from each of four rods. what is the least number of total pieces if he is to cut without any wastage?

Discussion & Comments