Question 1

Profit and Loss — A calculator sells at ₹ 250 each “including” a profit of 14% (per unit). If 7 calculators are sold per day for 19 days, compute the total profit earned.

Accepted Answer

Introduction / Context: The phrase “includes a profit of 14%” is commonly interpreted in such MCQs as a 14% margin computed per unit on the tagged piece price basis. With fixed units per day over fixed days, multiply per-unit profit by total units. Given Data / Assumptions: SP per calculator = ₹ 250 Profit% per calculator = 14% (interpreted on the piece price here to align with options) Quantity = 7 per day × 19 days Concept / Approach: Profit per unit = 14% of 250 = 0.14 * 250. Total profit = profit per unit * total units. Step-by-Step Solution: Profit per unit = 0.14 * 250 = ₹ 35Total units = 7 * 19 = 133Total profit = 35 * 133 = ₹ 4655 Verification / Alternative check: If treated as 14% on CP instead, the result would be ≈ ₹ 4083.33, which does not match any offered correct option; hence we adopt the per-piece interpretation consistent with choices. Why Other Options Are Wrong: ₹ 4665, ₹ 4565, and ₹ 4545 are close distractors from small arithmetic slips. ₹ 4085 approximates an alternative assumption but is not an option aligned with the stated framing. Common Pitfalls: Confusing whether the percentage applies to CP or SP. Always match the interpretation to the question’s phrasing and provided options. Final Answer: ₹ 4655

Question 2

Profit and Loss — The cost price of 24 apples equals the selling price of 18 apples. Determine the overall percentage gain.

Accepted Answer

Introduction / Context: Equal-value relationships across different counts translate directly to the SP/CP unit ratio. From that ratio, the gain% follows immediately. Given Data / Assumptions: 24 * CP_unit = 18 * SP_unit Concept / Approach: SP_unit / CP_unit = 24/18 = 4/3 = 1.333..., meaning a 33.333...% gain over cost. Step-by-Step Solution: SP_unit / CP_unit = 4/3Profit% = ((4/3 − 1) * 100) = (1/3 * 100) = 33.333...% Verification / Alternative check: Let CP_unit = ₹ 3 ⇒ cost for 24 apples = ₹ 72. Then SP_unit = ₹ 4 ⇒ revenue for 18 apples = ₹ 72. For all apples at SP_unit, gain% would be ((4 − 3)/3)*100 = 33.333...%. Why Other Options Are Wrong: 12.5%, 14.666...%, 16.666...%, and 25% do not match the exact 4/3 ratio implication. Common Pitfalls: Subtracting numbers of apples instead of forming the SP/CP ratio per unit. Final Answer: 33.333...%

Question 3

Profit and Loss — A watch sold at ₹ 405 incurs a 10% loss (so CP = ₹ 450). If it is sold at ₹ 465 instead, determine the new gain or loss percentage.

Accepted Answer

Introduction / Context: Knowing one transaction’s loss lets us recover CP. With CP known, any alternative SP can be compared to CP to find the new profit or loss% quickly. Given Data / Assumptions: SP_1 = ₹ 405 at 10% loss ⇒ CP = 405 / 0.90 = ₹ 450 New SP_2 = ₹ 465 Concept / Approach: Profit% (or loss%) is always measured on CP: (SP − CP)/CP * 100. Step-by-Step Solution: CP = 405 / 0.90 = 450Profit at SP_2 = 465 − 450 = ₹ 15Profit% = 15 / 450 * 100 = 3.333...% Verification / Alternative check: At SP_1 = 405, loss% = (450 − 405)/450 * 100 = 10% (consistent). At SP_2 = 465, result is a small profit ≈ 3.33%. Why Other Options Are Wrong: 10% profit, 6% loss, and no profit no loss contradict the computed margin; 3.33% loss has the wrong sign. Common Pitfalls: Using SP as the base instead of CP; profit and loss percentages are always on CP unless explicitly stated otherwise. Final Answer: profit of 3.33%

Question 4

Profit and Loss — A washing machine is listed at ₹ 10000 with successive discounts of 10% and 20%. The dealer then spends 10% of his purchase cost on transport. At what price should he sell to earn a 10% profit overall?

Accepted Answer

Introduction / Context: This problem combines successive discounts with an additional expense (transport) and a target profit on the total effective cost. It tests multi-step percentage handling. Given Data / Assumptions: List Price = ₹ 10000 Discounts: first 10%, then 20% Transport expense = 10% of dealer’s purchase cost (after discounts) Target profit = 10% on total cost (purchase + transport) Concept / Approach: Apply discounts successively: Price_after_discounts = 10000 * 0.90 * 0.80. Add transport at 10% of that purchase cost. Finally, multiply by 1.10 to achieve a 10% profit on the total cost base. Step-by-Step Solution: Price after discounts = 10000 * 0.90 * 0.80 = 7200Transport = 10% of 7200 = 720Total effective cost = 7200 + 720 = 7920Required SP for 10% profit = 7920 * 1.10 = 8712 Verification / Alternative check: Profit amount = 8712 − 7920 = 792 ⇒ 792/7920 * 100 = 10% exactly. Why Other Options Are Wrong: 8722 and 8840 deviate from the exact 10% profit. 7892 is below cost; 8800 overshoots the target profit. Common Pitfalls: Treating successive discounts as a single 30% discount on MRP without compounding (actual multiplier is 0.90 * 0.80 = 0.72). Another mistake is applying profit% on the pre-transport cost rather than on the full effective cost. Final Answer: ₹ 8712

Question 5

A person sells bananas at Rs 3 per piece and incurs a loss of Rs 20, but if he sells at Rs 3.25 per piece he gains Rs 30. Find the total number of bananas sold.

Accepted Answer

Introduction:This problem uses linear profit equations with the same unknown quantity. When the selling price per unit changes while the lot size stays fixed, the change in total profit is directly proportional to the change in price multiplied by the number of units. We translate the two scenarios into equations and solve for the number of bananas. Given Data / Assumptions: Selling price case 1: Rs 3 per banana → overall loss Rs 20 Selling price case 2: Rs 3.25 per banana → overall gain Rs 30 Let n be the number of bananas and c be the cost price per banana (rupees) Concept / Approach:If SP is p, total profit = n * (p − c). Loss is negative profit; gain is positive profit. Set up two equations and eliminate c to get n. This is a standard “two price points, one quantity” technique in profit and loss. Step-by-Step Solution:For Rs 3: n * (3 − c) = −20 ⇒ n * (c − 3) = 20For Rs 3.25: n * (3.25 − c) = 30Add the two (c − 3) + (3.25 − c) = 20/n + 30/n ⇒ 0.25 = 50/nHence n = 50 / 0.25 = 200 Verification / Alternative check:With n = 200, the price increase of Rs 0.25 raises revenue by 200 * 0.25 = Rs 50, which moves profit from −20 to +30 (a difference of Rs 50). Consistent. Why Other Options Are Wrong:100/120: Would yield revenue change 25 or 30, not enough to shift −20 to +30.2400: Would imply a profit swing of 600, far larger than observed. Common Pitfalls:Mixing up unit profit with lot profit; forgetting that loss is negative in the first equation; trying to determine the cost price first (it cancels out neatly). Final Answer:200

Question 6

A fruit seller claims to sell at cost price but uses a 450 g weight in place of 500 g. Find his percentage profit.

Accepted Answer

Introduction:False-weight problems are classic profit tricks. Even if the price tag equals the cost price per “kilogram,” giving less than a kilogram increases the effective selling price per true kilogram, creating a hidden margin. We compute the effective gain when 450 g is passed off as 500 g at the stated cost price. Given Data / Assumptions: Claimed selling price = cost price per 500 g unit (honest label) Actual quantity delivered per “500 g” sale = 450 g Let CP per kg = C rupees (unknown, cancels) Concept / Approach:If the seller charges for 500 g at the cost rate, the nominal charge for 500 g = 0.5 * C. But the buyer receives only 0.45 kg, so the revenue per true kg equals (0.5 * C) / 0.45. Compare this with the true cost per kg C to find the profit percentage. Step-by-Step Solution:Effective SP per true kg = (0.5 * C) / 0.45 = (10/9) * C ≈ 1.111... * CProfit% = [(Effective SP − C) / C] * 100 = (1.111... − 1) * 100 = 11.111...%11.111...% = 11 1/9 % Verification / Alternative check:On 0.45 kg: charged = 0.5 * C; cost to seller = 0.45 * C; gain = 0.05 * C; gain% on cost = (0.05/0.45)*100 = 11.111...%. Why Other Options Are Wrong:10%, 12%, 12 2/9%: These do not match 0.05/0.45 exactly. Common Pitfalls:Using 500/450 directly as profit%; forgetting to compute profit relative to the true cost per kg; mixing per-kg and per-500 g bases. Final Answer:11 1/9 %

Question 7

Two-thirds of a consignment is sold at a profit of 5% and the remainder at a loss of 2%. If the total profit is Rs 400, find the value (cost) of the entire consignment.

Accepted Answer

Introduction:When parts of a lot are sold at different percentages of gain or loss, the overall profit equals the weighted sum of those percentages applied to the corresponding cost portions. Here, the weights are two-thirds and one-third of total cost. Given Data / Assumptions: Fraction sold at profit 5%: 2/3 of total cost Fraction sold at loss 2%: 1/3 of total cost Total profit = Rs 400; Let total cost = C Concept / Approach:Overall profit = (2/3 * 5% * C) + (1/3 * −2% * C) = C * (0.05 * 2/3 − 0.02 * 1/3). Solve for C using the given absolute profit of Rs 400. Step-by-Step Solution:Profit = C * (0.10/3 − 0.02/3) = C * (0.08/3)So 400 = C * (0.08/3) ⇒ C = 400 * 3 / 0.08C = 1200 / 0.08 = 15000 Verification / Alternative check:Two-thirds of 15000 is 10000; 5% of that is 500. One-third is 5000; 2% loss is 100. Net profit = 500 − 100 = 400 (matches). Why Other Options Are Wrong:20000, 10000, 12000: Their weighted gains/losses do not produce Rs 400. Common Pitfalls:Applying percentages to selling price instead of cost; forgetting that the weights (2/3 and 1/3) apply to cost portions, not counts unless unit costs are uniform. Final Answer:15000

Question 8

A trader uses a faulty balance that shows 1250 g as 1 kg, and he also marks up his cost price by 20%. Find his overall profit percentage.

Accepted Answer

Introduction:Here, the trader benefits twice: by marking up the price and by under-delivering weight due to a miscalibrated balance. We compute the compound effect relative to the true cost of goods delivered. Given Data / Assumptions: Scale shows 1 kg when actual is 0.8 kg (since 1.25 kg shows as 1 kg, the factor is actual = shown / 1.25) Markup on cost price = 20% Let true cost per kg = C rupees Concept / Approach:For one “kg sale” (based on the faulty balance): revenue = 1.20 * C; actual quantity delivered = 0.8 kg; cost of delivered goods = 0.8 * C. Profit% is computed on the cost of goods delivered. Step-by-Step Solution:Revenue per sale = 1.2 * CCost per sale = 0.8 * CProfit = 1.2C − 0.8C = 0.4CProfit% = (0.4C)/(0.8C) * 100 = 50% Verification / Alternative check:Even without markup, under-delivery would create gain; with an added 20% markup, profit reaches exactly 50% under these parameters. Why Other Options Are Wrong:5%, 30%, 45%: Do not reflect the combined effect of 20% markup and giving only 0.8 kg. Common Pitfalls:Interpreting “shows 1250 g as 1 kg” backwards; computing profit on selling price instead of cost base of goods delivered. Final Answer:50 %

Question 9

Ragini buys oranges at Rs 10 per dozen and sells them at Rs 12 for every 10 oranges. Find her profit percentage.

Accepted Answer

Introduction:Convert both buying and selling terms to unit rates (per orange) and then compute profit percentage using the standard formula (SP − CP)/CP * 100. Mixed “per dozen” and “per ten” wordings often hide simple unit arithmetic. Given Data / Assumptions: CP: Rs 10 per 12 oranges → CP per orange = 10/12 SP: Rs 12 per 10 oranges → SP per orange = 12/10 Concept / Approach:Profit% = ((SP − CP) / CP) * 100 after computing per-piece prices. Keep exact fractions to avoid rounding errors. Step-by-Step Solution:CP per orange = 10/12 = 5/6 ≈ 0.8333SP per orange = 12/10 = 6/5 = 1.2Profit% = ((1.2 − 0.8333)/0.8333) * 100 = (0.3667/0.8333) * 100 ≈ 44% Verification / Alternative check:On 30 oranges: CP = (5/6)*30 = 25; SP = (6/5)*30 = 36; profit = 11; profit% = 11/25 * 100 = 44%. Why Other Options Are Wrong:40%, 48%, 60%: Do not match the exact ratio 6/5 versus 5/6. Common Pitfalls:Forgetting that dozen = 12; mixing up the bases (per 10 vs per 12) and doing a direct percentage on rupees rather than unit cost. Final Answer:44 %

Question 10

A merchant marks an article at Rs 300 and allows a 25% discount. If he still gains 12.25%, find the cost price of the article.

Accepted Answer

Introduction:This is a marked-price and discount problem culminating in a gain on cost. Convert the discount into the actual selling price and then relate it to cost via the gain percentage to solve for the cost price (CP). Given Data / Assumptions: Marked Price (MP) = Rs 300 Discount = 25% → Selling Price (SP) = 300 * (1 − 0.25) = Rs 225 Gain% on cost = 12.25% (≈ 0.1225) Concept / Approach:SP = (1 + gain%) * CP. Substitute SP = 225 and gain% = 0.1225 to compute CP. Minor rounding is acceptable if the nearest standard option matches the implied CP closely. Step-by-Step Solution:225 = (1 + 0.1225) * CP = 1.1225 * CPCP = 225 / 1.1225 ≈ 200.44...Closest standard cost price in options = Rs 200 Verification / Alternative check:If CP = 200, gain% = (225 − 200)/200 * 100 = 12.5%, which is within rounding proximity to 12.25% stated (typical exam rounding/typo scenario). Among listed options, Rs 200 is the intended choice. Why Other Options Are Wrong:220/240/260: Do not reconcile with SP = 225 and gain near 12%. Common Pitfalls:Applying discount on cost instead of marked price; computing gain on SP rather than CP. Final Answer:200

Question 11

A retailer cheats both the wholesaler and his customers by 10% using a faulty balance: he weighs 10% more while buying and 10% less while selling, and sells at the listed cost price. Find his net profit percentage.

Accepted Answer

Introduction:The retailer gains twice: he receives extra quantity when purchasing, and he delivers less when selling. Even if he “sells at cost price” per kg (nominal), the net effect is a profit when measured against the true cost of goods delivered. We quantify the combined effect. Given Data / Assumptions: Buys: for each 1 kg paid, receives 1.1 kg (10% extra) Sells: for each 1 kg billed, delivers 0.9 kg (10% short) Nominal selling price per kg equals listed cost price per kg = C Concept / Approach:For one “kg sale”: revenue = C. True cost of the 0.9 kg delivered equals 0.9 times the true cost per kg the retailer effectively paid. Since he got 1.1 kg for the price of 1 kg, his true cost per kg is C/1.1. Compute profit% on cost of goods delivered. Step-by-Step Solution:Cost per true kg to retailer = C / 1.1Cost for 0.9 kg delivered = (C / 1.1) * 0.9 = 0.81818... * CRevenue per sale = CProfit = C − 0.81818... C = 0.18181... CProfit% = 0.18181... / 0.81818... * 100 = 22.222...% = 22 2/9% Verification / Alternative check:On 11 kg bought (paying 10 kg): he sells in “1 kg” lots, each delivering 0.9 kg; 11 kg supports 12.22... “kg” bills—consistent with a 22.22...% edge overall. Why Other Options Are Wrong:20%, 21%: Understate the compounding of the two 10% cheats.22 2/2%: Not a standard fraction here; correct exact value is 22 2/9%. Common Pitfalls:Computing profit% on selling price; ignoring that cost per true kg is reduced by the 10% extra received at purchase. Final Answer:22 2/9%

Question 12

A vendor sells at an actual profit of p%. If he instead sells at one-third of his actual selling price, he incurs a 40% loss. Find p (the actual profit percentage).

Accepted Answer

Introduction:Link profit on cost to a hypothetical selling price that is one-third of the real selling price. The switch turns a gain into a loss, allowing us to back out the original profit percentage using a simple ratio relation. Given Data / Assumptions: Let CP = C Actual SP = S = (1 + p) * C If SP becomes S/3, loss = 40% ⇒ (S/3 − C)/C = −0.4 Concept / Approach:From (S/3) = 0.6 * C, deduce S = 1.8 * C. Since S = (1 + p) * C, compare coefficients to find p. Step-by-Step Solution:S/3 = 0.6 * C ⇒ S = 1.8 * CBut S = (1 + p) * C ⇒ 1 + p = 1.8 ⇒ p = 0.8 = 80% Verification / Alternative check:With C = 100, S = 180 (profit 80). At S/3 = 60, loss = 40 on C = 100 → −40% (matches). Why Other Options Are Wrong:72%, 120%, 60% do not satisfy S/3 = 0.6C. Common Pitfalls:Using 40% on SP; forgetting that loss% is always on CP. Final Answer:80%

Question 13

A 20% reduction in the price of sugar enables a housewife to buy 6 kg more for Rs 240. Find the original price per kilogram.

Accepted Answer

Introduction:Price reduction with fixed budget increases quantity purchased. Setting up quantities before and after the reduction yields a simple linear equation in the original price per kilogram. Given Data / Assumptions: Budget = Rs 240 Original price = x rupees/kg New price after 20% cut = 0.8x Increase in quantity = 6 kg Concept / Approach:Quantity before = 240/x. Quantity after = 240/(0.8x) = 300/x. The difference equals 6, giving an equation in x. Step-by-Step Solution:300/x − 240/x = 660/x = 6 ⇒ x = 10Original price = Rs 10 per kg Verification / Alternative check:At Rs 10/kg, old quantity = 24 kg; new price = Rs 8/kg → new quantity = 30 kg; increase = 6 kg (consistent). Why Other Options Are Wrong:8/6/5: These give differences not equal to 6 kg with the given budget. Common Pitfalls:Applying 20% to quantity or budget rather than price; arithmetic slips with proportions. Final Answer:Rs. 10 per kg

Question 14

Due to a 25% reduction in the price of oranges, a customer can buy 4 more oranges for Rs 16. Find the original price per orange.

Accepted Answer

Introduction:Again, a fixed budget with a price cut increases quantity. We form equations using unit prices before and after a 25% reduction and equate the difference in quantities to 4. Given Data / Assumptions: Budget = Rs 16 Original price = p rupees/orange New price after 25% cut = 0.75p Increase in count = 4 oranges Concept / Approach:Original count = 16/p; new count = 16/(0.75p) = 64/(3p). The difference equals 4; solve for p. Step-by-Step Solution:64/(3p) − 16/p = 4(64 − 48)/(3p) = 4 ⇒ 16/(3p) = 4 ⇒ 16 = 12p ⇒ p = 4/3Original price = Rs 1.333... = Re. 1.33 (rounded) Verification / Alternative check:At p = 4/3, old count = 12; new price = 1; new count = 16; increase = 4, consistent. Why Other Options Are Wrong:1.0/1.5/1.6 do not satisfy the exact difference of 4 at Rs 16. Common Pitfalls:Using 25% of Rs 16 (budget) incorrectly; rounding too early. Final Answer:Re. 1.33

Question 15

A house has a list price of Rs 8 lakh. Kamal gets successive discounts of 20% and 10% (cash). He then spends 10% of the cost price on interiors and lawn. At what selling price should he sell to earn a 25% profit?

Accepted Answer

Introduction:Successive discounts multiply, not add. After computing the effective purchase price, we add post-purchase expenditure (as a percentage of cost) to get the total cost base. Finally, we apply the target profit on this base to find the required selling price. Given Data / Assumptions: List price = Rs 8,00,000 Discounts: 20% then 10% Additional spend = 10% of cost price Desired profit = 25% on total cost Concept / Approach:Effective discount factor = 0.8 * 0.9 = 0.72. Add 10% of CP to get total cost. Then multiply by 1.25 to reach the target selling price. Step-by-Step Solution:Initial CP = 8,00,000 * 0.72 = 5,76,000Additional spend = 10% of 5,76,000 = 57,600Total cost = 5,76,000 + 57,600 = 6,33,600Required SP = 1.25 * 6,33,600 = 7,92,000 Verification / Alternative check:Profit = 7,92,000 − 6,33,600 = 1,58,400, which is 25% of 6,33,600. Why Other Options Are Wrong:9 lakh too high (exceeds 25% on total cost). 7.99 lakh is not exact; correct figure is 7.92 lakh. Common Pitfalls:Adding discounts (20% + 10% ≠ 30%); applying 10% interior cost to list price instead of to CP. Final Answer:Rs. 7.92 lakh

Question 16

A retailer buys 20 kg of tea at a 10% discount on the marked price, and also gets 1 kg free on purchasing 20 kg. He sells the entire stock at the marked price. Find his profit percentage.

Accepted Answer

Introduction:This combines a price discount with a quantity bonus. The retailer’s cost is reduced by the discount, and his saleable quantity is increased by the free units. Selling at MRP yields a clean profit computation. Given Data / Assumptions: Marked price per kg = M Buys 20 kg at 10% off → cost = 20 * 0.9M = 18M Gets 1 kg free → total quantity to sell = 21 kg Sells all at MRP → revenue = 21M Concept / Approach:Profit% is computed on cost: (Revenue − Cost)/Cost * 100. Using symbolic M cancels unknowns neatly. Step-by-Step Solution:Profit = 21M − 18M = 3MProfit% = 3M / 18M * 100 = 16.666...% Verification / Alternative check:Even with any absolute M, the ratio remains 1/6 due to proportionality. Why Other Options Are Wrong:12% and 14.28% understate; 30% overstates as if both benefits compounded differently. Common Pitfalls:Forgetting to include the free quantity in revenue potential; treating 10% off as 10% of selling price. Final Answer:16.66%

Question 17

The marked price of an article is increased by 25% and the selling price is increased by 16.66%. As a result, the profit doubles. If the original marked price is Rs 400 and exceeds cost by 33.33%, find the increased selling price.

Accepted Answer

Introduction:This problem ties the original selling price to the new selling price through the condition that profit doubles. The given relationship between the original marked price and cost allows us to express profit in terms of the original selling price and then scale it by the specified 16.66% increase. Given Data / Assumptions: Original MP = Rs 400, which is 33.33% above cost ⇒ CP = 400 / (1 + 1/3) = 300 Let original SP = S; new SP = S * (1 + 1/6) = (7/6)S Profit doubles: (New SP − CP) = 2 * (Original SP − CP) Concept / Approach:Form the doubling equation with CP = 300 and solve for S, then compute the increased SP. Step-by-Step Solution:(7/6)S − 300 = 2(S − 300)(7/6)S − 300 = 2S − 600(7/6 − 2)S = −300 ⇒ (−5/6)S = −300 ⇒ S = 360Increased SP = (7/6) * 360 = 420 Verification / Alternative check:Original profit = 360 − 300 = 60; new profit = 420 − 300 = 120 (double), as required. Why Other Options Are Wrong:240/360 too low; 600 too high relative to the doubling condition. Common Pitfalls:Adding 25% and 16.66% directly; confusing profit doubling on CP with a standalone % change in SP. Final Answer:420

Question 18

A trader’s balance weighs 10% less than true weight. He still wants an overall profit of 20%. What markup on cost price is required (no discount assumed)?

Accepted Answer

Introduction:Under-weighing means that when the trader bills 1 kg, the customer actually receives only 0.9 kg. If the trader also marks up his price, we can choose the markup so that the net profit on the cost of goods delivered is exactly 20%. Given Data / Assumptions: True cost per kg = C Actual quantity delivered for a “1 kg” sale = 0.9 kg Required overall profit = 20% Let markup on cost = m (so SP for 1 “kg” = C * (1 + m)) Concept / Approach:Profit% on cost of goods delivered = [(Revenue − Cost)/Cost] * 100. Here, Cost = 0.9 * C and Revenue = C * (1 + m). Set this profit equal to 20% and solve for m. Step-by-Step Solution:Profit% = [(C(1 + m) − 0.9C) / (0.9C)] * 100 = [(0.1 + m)/0.9] * 100Set [(0.1 + m)/0.9] = 0.20 ⇒ 0.1 + m = 0.18 ⇒ m = 0.08Required markup = 8% Verification / Alternative check:Revenue at m = 8%: 1.08C; cost of 0.9 kg = 0.9C; profit% = 0.18C / 0.9C = 20%. Why Other Options Are Wrong:16.66% or 25% overshoot; 40% is excessive for a 10% under-weight scenario at 20% target profit. Common Pitfalls:Calculating profit on selling price base; forgetting that the under-weighing already contributes part of the margin (0.1/0.9 ≈ 11.11%). Final Answer:8%

Question 19

A scientific calculator is Rs M at Universal Shoppe (Hazratganj) with 20% discount and Rs M at Universal Shoppe (Bhootnath) with 15% discount. Ms. Agrawal has exactly Rs 800 to buy at Hazratganj. How much less than required is she to buy at Bhootnat…

Accepted Answer

Introduction:Equal MRPs at two stores, different discounts. If an amount exactly matches the discounted price at one store, we can recover the MRP and then compute the price (and shortfall) at the other store. Given Data / Assumptions: At Hazratganj: price = 0.8 * M = Rs 800 ⇒ MRP M = Rs 1000 At Bhootnath: price = 0.85 * M Concept / Approach:Compute the Bhootnath price using the recovered MRP and compare it with the amount available (Rs 800) to find the shortfall. Step-by-Step Solution:M = 800 / 0.8 = 1000Bhootnath price = 0.85 * 1000 = Rs 850Shortfall = 850 − 800 = Rs 50 Verification / Alternative check:Reverse check: 20% discount on 1000 is 800 (fits the “just sufficient” statement). Why Other Options Are Wrong:70/100 are not consistent with 15% discount on Rs 1000; data is sufficient. Common Pitfalls:Assuming different MRPs; confusing percent of price with absolute rupees before solving for M. Final Answer:Rs. 50

Question 20

A seller computes profit on selling price instead of cost price. By selling an article for Rs 280, he reports a profit of 14 2/7% (on SP). Find his actual profit percentage on cost.

Accepted Answer

Introduction:Reporting profit on selling price (SP) understates the base; converting the stated figure into an actual rupee profit and then dividing by true cost yields the correct profit percentage on cost price (CP). Given Data / Assumptions: SP = Rs 280 Reported profit% on SP = 14 2/7% = 100/7% ≈ 14.2857% Concept / Approach:Profit (rupees) = (reported% of SP). Actual CP = SP − profit. Then Actual Profit% = profit / CP * 100. Step-by-Step Solution:Profit (rupees) = (100/7)% of 280 = (1/7) * 280 = 40Actual CP = 280 − 40 = 240Actual Profit% = 40 / 240 * 100 = 16.666...% Verification / Alternative check:If profit were computed on CP: 16.66% of 240 is 40, bringing SP to 280 (consistent). Why Other Options Are Wrong:20%/25% overstate; 12.5% understates. Common Pitfalls:Applying 14 2/7% on CP by mistake; mixing up the definition of base. Final Answer:16.66 %

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