If x = 2 + 223 + 213 then find the value of x3-6x2+6x ?

Given that  $x = 2+ 2\frac{2}{3} + 2\frac{1}{3}$

So x - 2 =  $2\frac{2}{3} + 2\frac{1}{3}$

Now cubing on both sides, we get

=>  $x3-8-6x2+12x = 4 + 2 + 6(x-2)$

Therefore,  $x3-6x2+6x = -6 + 8 = 2$