What should come in place of both the question marks in the equation ?128=162?

Let  $\frac{x}{128}=\frac{162}{x}$

Then,  $x2=128\times 162 =64\times 2\times 18\times 9=82\times 62\times 32 = 8\times 6\times 3 =144$

$\therefore x=12$