A tiger is 50 of its own leaps behind a deer. The tiger takes 5 leaps per minute to the deer's 4. If the tiger and the deer cover 8 m and 5 m per leap respectively, what distance will the tiger have to run before it catches the deer?
Correct Answer: 800 m
Explanation:
Speed of tiger = 40 m/min
Speed of dear = 20 m/min
Relative speed = 40 - 20 = 20 m/min
Difference in distance = 50 x 8 = 400 m
∴ Time taken in overtaking (or catching) = 400/20 = 20min
∴ Distance travelled in 20 min = 20 x 40 = 800 m
