12 men can complete a work in 8 days. 16 women can complete the same work in 12 days. 8 men and 8 women started working and worked for 6 days. How many more men are to be added to complete the remaining work in 1 day?

1 man's 1 day work =1/96 ; 1 woman's 1 day work = 1/192

Work done in 6 days= $6\frac{8}{96}+\frac{8}{192}=6\times \frac{1}{8} =\frac{3}{4}$ 

Remaining work = 1/4

(8 men +8 women)'s 1 day work =  $1\frac{8}{96}+\frac{8}{192}$ =1/8

Remaining work =1/4 -  1/8 = 1/8

 1/96 work is done in 1 day by 1 man

Therefore, 1/8 work will be done in 1 day by 96 x (1/8) =12 men