Let lengths, breadth and height of cuboid be l, b and h respectively
According to question
l+b+h = 22cm......(i)
and
√(l^2+b^2+h^2) = 14cm .....(ii)
Surface area of cuboid = 2(lb+bh+lh)
Squaring eq (i) gives
+ 2(lb+bh+lh) = 484
Substituting l^2+b^2+h^2 from eq (i)
2(lb+bh+lh) = 484 -196 = 288 sq.cm
