Striking-clock interval logic: If a clock strikes 6 times in 5 seconds, how many times will it strike in 10 seconds?

Introduction / Context:For striking clocks, the duration refers to the time between the first and last strike, i.e., to the number of intervals, which is strikes − 1. If 6 strikes take 5 seconds, then each interval lasts 1 second. Scale this to the requested time span.

Given Data / Assumptions:

• 6 strikes in 5 seconds ⇒ 5 intervals in 5 s ⇒ 1 s per interval.
• We want the number of strikes that can occur over 10 seconds.

Concept / Approach:Number of intervals in 10 seconds = 10/1 = 10. Strikes = intervals + 1 = 11.

Step-by-Step Solution:

Verification / Alternative check:Check proportionality: doubling duration doubles the number of intervals; the strike count grows by one beyond those intervals.

Why Other Options Are Wrong:10/9/8 are counts of intervals, not strikes, or undercounts the extra end strike.

Common Pitfalls:Confusing “strikes” with “intervals between strikes.”

Final Answer:11